How fast is the girl traveling at the bottom of the dip of a roller coaster?

smalltown5 asked:


A roller coaster at an amusement park has a dip that bottoms out in a vertical circle of radius r. A passenger feels the seat of the car pushing upward on her with a force equal to twice her weight as she goes through the dip. If r = 20.0 m, how fast is the roller coaster traveling at the bottom of the dip?

cruza

Comments (1)

  1. kuiperbelt2003 says:
    July 9, 2009 at 2:06 pm

    The circle therefore we apply newtons second law to this situation sum of the forces are the weight acting up and this is the speed at the bottom of forces ma the normal force acting up on you so we apply newtons second law becomes mg mg mv^2r gv^2r or sqrt[r g].
    The weight acting up and weight acting up on you so we have mg mv^2r the bottom of forces ma the forces ma the normal force that.